## Solve the equation x^4 - 4x^2 + 8x + 35 = 0 having one root as 2 + i*sqrt(3).

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The given equations are ax + by = 1 and cx^2 + dy^2 = 1....

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Two numbers a1, b1 are formed from given numbers a, b by the relation 3a1 = 2a + b, 3b1 = a + 2b. Similarly a2, b2 are formed from a1, b1 in the same manner and so on....

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Given that A, B are roots of X^2 + px + 1 = 0 and C, D are roots of x^2 + qx + 1 = 0....

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Note that sn = sum of first n natural numbers....

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Note that the solution r = n/2 is omitted if n is even....

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z1, z2 and z3 are complex numbers....

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Given that p and q are complex numbers and q is not equal to 0....

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The sides of the square are equal to a....

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The given lines are x*sqrt(3)+y=0; y*sqrt(3)+x=0; x*sqrt(3)+y=1; y*sqrt(3)+x=1....

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The two given lines are represented by the equation a*x^2 + b*y^2 + 2hxy + 2gx + 2fy + c = 0....

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